TechTalk7

In Unity, assembly can be used to accelerate compiling.
I used to believe that if one script changed, only its containing assembly is recompiled.

I did some experiments today, and find that not only the containing assembly is recompiled.
For example, Assembly-CSharp.dll is recompiled most of the time.

Assume script ‘a’ belongs to assembly ‘A’.
Based on my experiments, adding/deleting public field or method, assemblies that reference ‘A’ will be recompiled. Modifying content of a public method will not cause referencing assemblies to be recompiled. adding/deleting/modifying private things will not cause referencing assemblies to be recompiled either.

So, which assemblies will be recompiled if I change one script in Unity?
Is there any article or book about this?

I’m trying to call my Google Cloud Function via HTTP to get a response back in my browser. I expect a list of text, but am getting Error: could not handle the request.

Here’s our code in the main.py source:

import openai

def gptinput(number,question,q_fc='q'):
    #user_information = firebase.FirebaseReader()
    openai.api_key = "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"
quest = "create '"+str(number)+ "' questions related to '"+question+"' with 4 options and print answer as ('ANSWER') and seperate each question with '/////'"
# Generate text using GPT-3
output_lis = []
while(len(output_lis)<number):

  response = openai.Completion.create(
      engine="text-davinci-002",
      prompt= quest,
      max_tokens=2048,
      n=1,
      stop=None,
      temperature=0.5
      )
      # Extract the generated text
  
  generated_text = response["choices"][0]["text"]
  ans = generated_text.split("/////")
  for i in ans:
    q = i.split('?')
    options= q[1][0:q[1].find("ANSWER")]
    answer = q[1][q[1].find("ANSWER")+6:]
    answer = answer.strip()
    
    option_lis = options.split('\n')
    option_lis.append(answer)
    
    ques = q[0].strip()
    option_lis = [s for s in option_lis if (s!='' or s!="")]
    option_lis1 = [s for s in option_lis if (s!="\n" )]

    output_lis.append({ques:option_lis1})
    
return output_lis[0:number]
  `